Answer:
(c)
Impulse
\[(F\times t)=\] Change in momentum
\[\therefore
\]\[F=\,\frac{2mv}{t}=\,\frac{2\times 0.15\,\times 35\,}{{{10}^{-3}}}\]
\[=1.05\times
{{10}^{4}}\,N\]
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