Answer:
Mass of bullet, m = 0.012 kg
Speed of bullet,
Mass of block, M = 0.4 kg
If V is the velocity of the
combination after collision, then from the law of conservation of momentum,
or
Let be the height through which
the block rises. Then from the conservation of energy,
P.E. of the combination = K.E.
of the combination
or
Amount of heat produced
= Loss in K.E. of the bullet
= Initial K.E. of the bullet
- K.E. of the
combination
= 29.4 - 0.86 =
28.54 J.
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