Answer:
(a) \[\theta
=\frac{\text{Diameter of earth}}{R}\]
\[=\frac{2{{R}_{E}}}{60{{R}_{E}}}\]
\[=\frac{1}{30}\text{red}\]
\[=\frac{1}{30}\times \frac{360{}^\circ
}{2\pi }\]
\[=1.91{}^\circ \approx 2{}^\circ \]
(b) Diameter of earth as seen from moon \[={{2}^{o}}\]
Diameter of earth as seen from moon \[=\frac{{{1}^{o}}}{2}\]
\[\therefore \]\[\frac{\text{Diameter of
earth}}{\text{Diameter of moon}}=\frac{2{}^\circ }{1/2{}^\circ }=4\]
(c) \[\frac{{{R}_{S}}}{{{R}_{M}}}=400,\]
Now \[\frac{{{D}_{S}}}{{{D}_{M}}}=\frac{{{R}_{S}}}{{{R}_{M}}}=400\]
Also \[\frac{{{D}_{E}}}{{{D}_{M}}}=4\]\[\therefore
\]\[\frac{{{D}_{s}}}{{{D}_{E}}}=\frac{{{D}_{S}}/{{D}_{M}}}{{{D}_{E}}/{{D}_{M}}}\]
\[=\frac{400}{4}=100\]
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