Answer:
(a), (b), (d) \[h=[M{{L}^{2}}{{T}^{-1}}]\]
\[c=[L{{T}^{-1}}]\]
\[G=[{{M}^{-1}}{{T}^{3}}{{T}^{-2}}]\]
\[\therefore \] \[M=\sqrt{\frac{hc}{a}}C=\sqrt{\frac{hc}{{{c}^{3}}}}\]
and \[T=\sqrt{\frac{ha}{{{c}^{5}}}}\]
Refer HOT NP No. 16.
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