Answer:
(c) \[Y=1.9\times {{10}^{11}}\,N/{{m}^{2}}\]
\[=1.9\times {{10}^{11}}\times
{{10}^{5}}\,\text{dyne}/{{10}^{4}}\,c{{m}^{2}}\]
\[=1.9\times {{10}^{12}}\times
\text{dyne}/c{{m}^{2}}\]
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