11th Class Physics Physical World / भौतिक जगत

  • question_answer 42)
                      Young?s modulus of steel is \[1.9\times {{10}^{11}}N/{{m}^{2}}\]. When expressed in CGS units of dynes/\[c{{m}^{2}}\], it will be         equal to \[(1N={{10}^{5}}\,\,\text{dyne},\text{ }1{{m}^{2}}=104\text{ }c{{m}^{2}})\]                 (a) \[1.9\times {{10}^{10}}\]                        (b) \[1.9\times {{10}^{11}}\]                 (c) \[1.9\times {{10}^{12}}\]                        (d) \[1.9\times {{10}^{13}}\]                

    Answer:

                      (c) \[Y=1.9\times {{10}^{11}}\,N/{{m}^{2}}\]                 \[=1.9\times {{10}^{11}}\times {{10}^{5}}\,\text{dyne}/{{10}^{4}}\,c{{m}^{2}}\]                 \[=1.9\times {{10}^{12}}\times \text{dyne}/c{{m}^{2}}\]                


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