Answer:
(a) \[AB=(2.5\times 0.10)\pm \left(
\frac{0.5}{2.5}+\frac{0.01}{0.10} \right)(2.5\times 0.10)\]
\[=0.25\text{ }m\pm 0.08\text{ }m\]
\[=\left( 0.25\pm 0.08 \right)\text{ }m\]
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