Answer:
Here, \[=2\cdot 74\times {{10}^{-5}}\]
Length at temperature, \[7\times
{{10}^{6}}Pa.\]cm.
Length at temperature, \[\text{L=10
cm}=0\cdot \text{10 m; p}=7\times {{10}^{6}}\text{Pa;}\]cm.
Change in length \[\text{ B=140
GPa}=140\times {{10}^{9}}Pa\]
or \[B=\frac{pV}{\vartriangle
V}=\frac{p{{L}^{3}}}{\vartriangle V}\text{ or }\vartriangle
V=\frac{p{{L}^{3}}}{B}\]
or \[=\frac{\left( 7\times
{{10}^{6}} \right)\times {{\left( 0\cdot 10 \right)}^{3}}}{140\times
{{10}^{9}}}\]
or \[=5\times
{{10}^{-8}}{{m}^{3}}\]
You need to login to perform this action.
You will be redirected in
3 sec