Answer:
Let \[{{\theta
}_{1}}\] be
the temperature at which Celsius and Fahrenheit scales coincide, i.e., \[{{t}_{C}}={{t}_{F}}={{\theta
}_{1}}\].
From
\[{{t}_{C}}=\frac{5}{9}({{t}_{F}}-32),\,{{\theta }_{1}}=\frac{5}{9}({{\theta
}_{1}}-32)\]
or
\[9{{\theta }_{1}}=5{{\theta }_{1}}-160\] or \[{{\theta }_{1}}=-{{40}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec