11th Class Physics Thermal Properties of Matter / द्रव्य के तापीय गुण

  • question_answer 25)
                      The graph between two temperature scales A and B is shown in Fig. Between upper fixed point and lower fixed point there are 150 equal division on scale A and 100 on scale B. The relationship for conversion between the two scales is given by (a) \[\frac{{{t}_{A}}-180}{100}\,=\,\frac{{{t}_{B}}}{150}\] (b) \[\frac{{{t}_{A}}-30}{150}\,=\,\frac{{{t}_{B}}}{100}\] (c) \[\frac{{{t}_{B}}-180}{150}\,=\,\frac{{{t}_{A}}}{100}\] (d) \[\frac{{{t}_{B}}-40}{100}\,=\,\frac{{{t}_{A}}}{180}\]                

    Answer:

                      (b) When \[{{t}_{B}}=\,0,\,{{t}_{A}}\,={{30}^{o}}\]                 \[\therefore \] \[\frac{{{t}_{A}}-\,30}{150}\,\,=\,\frac{{{t}_{B}}}{100}\]                


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