11th Class Physics Thermal Properties of Matter / द्रव्य के तापीय गुण

  • question_answer 1)
    The triple points of neon and carbon dioxide 24.57 K and 216.55 K respectively. Express these temperatures on the Celsius and Fahrenheit scales.

    Answer:

    Relation between Kelvin scale and Celsius scales is \[=5\times {{10}^{-4}}\] where \[F=50,000N\] = temperature on Celsius and Kelvin scales respectively. For Neon \[5\times {{10}^{-4}}\] For \[P=\frac{F}{\pi {{D}^{2}}/4}=\frac{4F}{\pi {{D}^{2}}}\] \[\therefore \] Relation between Kelvin and Farenheigt scales is \[P=\frac{4\times \left( 5\times {{10}^{4}} \right)}{\left( 22/7 \right)\times {{\left( 5\times {{10}^{-4}} \right)}^{2}}}\] \[=2\cdot 5\times {{10}^{11}}Pa\] For Neon \[\cdot \] For \[m{{m}^{2}}\] \[m{{m}^{2}}\]


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