question_answer 51)

                  Show that for a particle executing S.H.M. velocity and displacement have a phase difference of \[\pi /2\].

Answer:

                  In S.H.M. \[y=r\sin \,\omega t\] and \[\upsilon =r\,\omega \,\cos \,\omega t\]\[=r\omega \sin \,(\omega t+\pi /2)\]                 Thus, phase difference \[\upsilon \] and \[y\] is \[\pi /2\].