11th Class Physics Oscillations / दोलन

  • question_answer 20)
    An air chamber of volume V has a neck area of cross section A into which a ball of mass m just fits and can move up and down without any friction, Fig. 10 (NCT). 7. Show that when the ball is pressed down a little and released, it executes SHM. Obtain an expression for the time period of oscillations assuming pressure volume variations of air to be isothermal.

    Answer:

    Consider an air chamber of volume V with a long neck of uniform area of cross-section A, and a frictionless ball of mass m fitted smoothly in the neck at position C, Fig. 10 (NCT). 7. The pressure of air below the ball inside the chamber is equal to the atmospheric pressure. Increase the pressure on the ball by a little amount p, so that the ball is depressed to position D, where CD = y. There will be decrease in volume and hence increase in pressure of air inside the chamber. The decrease in volume of the air inside the chamber. \[{{\text{a}}_{\text{c}}}\text{=}\frac{{{\text{ }\!\!\upsilon\!\!\text{ }}^{\text{2}}}}{\text{R}}\] Volumetic strain \[\text{g }\!\!'\!\!\text{ =}\sqrt{{{\text{g}}^{\text{2}}}\text{+}\frac{{{\text{ }\!\!\upsilon\!\!\text{ }}^{\text{4}}}}{{{\text{R}}^{\text{2}}}}}\]\[\therefore \] \[\text{T=2 }\!\!\pi\!\!\text{ }\sqrt{\frac{\text{l}}{\text{g }\!\!'\!\!\text{ }}}\text{=2 }\!\!\pi\!\!\text{ }\sqrt{\frac{\text{l}}{{{\text{g}}^{\text{2}}}\text{+}{{\text{ }\!\!\upsilon\!\!\text{ }}^{\text{4}}}\text{/}{{\text{R}}^{\text{2}}}}}\] Bulk Modulus of elasticity E, will be \[{{\text{ }\!\!\rho\!\!\text{ }}_{\text{1}}}\] \[\text{T=2 }\!\!\pi\!\!\text{ }\sqrt{\frac{\text{h }\!\!\rho\!\!\text{ }}{{{\text{p}}_{\text{1}}}\text{g}}}\] Here, negative sign shows that the increase in pressure will decrease the volume of air in the chamber. \[\text{ }\!\!\rho\!\!\text{ }\] \[\vartriangle \text{V=Ay}\] Due to this excess pressure, the restoring force acting on the ball is \[\text{=}\frac{\text{change in volume}}{\text{original volume}}\] Clearly, \[=\frac{\vartriangle V}{V}=\frac{\text{Ay}}{\text{V}}\] Negative sign shows that the force is directed towards equilibrium position. If the applied increased pressure is removed from the ball, the ball will start executing linear SHM in the neck of chamber with C as mean position. In S.H.M., the restoring force, \[F=-ky\].. (ii) Comparing (i) and (ii), we have \[\therefore \], which is the spring factor. Now, inertia factor = mass of ball = m. As, \[\text{E=}\frac{\text{stress}\left( \text{orincrease in pressure} \right)}{\text{volumetric strain}}\] \[\text{=}\frac{\text{-p}}{\text{Ay/V}}\text{=}\frac{\text{-pV}}{\text{Ay}}\] \[\therefore \] Frequency, \[\text{p=}\frac{\text{-EAy}}{\text{V}}\] Note. If the ball oscillates in the neck of chamber under isothermal conditions, then E = P = pressure of air inside the chamber, when ball is at equilibrium position. If the ball oscillates in the neck of chamber under adiabatic conditions, then \[\text{F=p }\!\!\times\!\!\text{ A=}\frac{\text{-eaY}}{\text{v}}\text{.A=}\frac{\text{-E}{{\text{A}}^{\text{2}}}}{\text{V}}\text{y }......\text{(i)}\] where\[F\alpha y;\]


You need to login to perform this action.
You will be redirected in 3 sec spinner