Answer:
(i) When the monkey climbs up with an acceleration the tension T
in the string must be greater than the weight of the monkey [Fig. 5.135(fl)],
or .
(ii) When the monkey climbs down
with an acceleration,
[Fig.
5.135(b)],
or T = m(g - a) = 40(10
- 4) = 240 N.
(iii) When the monkey climbs up
with uniform speed,
T
= mg = 40 x 10 = 400 N.
(iv) When the monkey falls down
the rope nearly )n freely, a = g
.
As the tension in the rope in case (i)
is greater than the maximum permissible tension (600 N), so the rope will break
in case (i) only.
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