11th Class Physics Laws Of Motion / गति के नियम

  • question_answer 32)
    A monkey of mass 40 kg climbes on a rope which can stand a maximum tension of 600 N [Fig. 5.134]. In which of the following cases will the rope break : the monkey (i) climbs up with an acceleration of (ii) climbs down with an acceleration of   (iii) climbs up with a uniform speed of (iv) falls down the rope nearly freely under gravity ? Take . Ignore the mass of the rope.   Fig. 5.134                             Fig. 5.135  

    Answer:

    (i) When the monkey climbs up with an acceleration  the tension T in the string must be greater than the weight of the monkey [Fig. 5.135(fl)],   or             . (ii) When the monkey climbs down with an acceleration,            [Fig. 5.135(b)],   or          T = m(g - a) = 40(10 - 4) = 240 N. (iii) When the monkey climbs up with uniform speed,                T = mg = 40 x 10 = 400 N. (iv) When the monkey falls down the rope nearly )n  freely, a = g             . As the tension in the rope in case (i) is greater than the maximum permissible tension (600 N), so the rope will break in case (i) only.  


You need to login to perform this action.
You will be redirected in 3 sec spinner