11th Class Physics Laws Of Motion / गति के नियम

  • question_answer 24)
    Fig. 5.132 shows a man standing stationary with respect to a horizontal conveyor belt that is accelerating with . What is the net force on the man ? If the coefficient of static friction between the man's shoes and the belt is 0.2, up to what acceleration of the belt can the man continue to be stationary relative to the belt ? Mass of the man = 65 kg.   Fig. 5.132  

    Answer:

    As the man is standing stationary w.r.t. the belt,  Acceleration of the man = Acceleration of the belt Mass of the man, m = 65 kg Net force on the man. Given coefficient of friction,  Limiting friction,   If the man remains stationary w.r.t. the maximum acceleration a' of the belt, then                                  


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