Answer:
For a ball dropped from a
building, speed in the downward direction after time t is given by
\[{{\upsilon
}_{{{y}_{1}}}}=\,0\,+\,gt\,=\,\,-\,10t\]
For a ball thrown up with \[\upsilon
=40\,m{{s}^{-1}}\],
Speed after time t is given
by \[{{\upsilon }_{{{y}_{2}}\,}}=\,40\,-\,10t\]
\ Relative speed of balls \[={{\upsilon
}_{{{y}_{2}}}}-{{\upsilon }_{{{y}_{1}}}}\]\[=40\,m{{s}^{-1}}\]
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