Answer:
\[x(t)\,=\,{{x}_{0}}\,(1\,-{{e}^{-\gamma
t}});\] \[\upsilon (t)\,=y\,{{k}_{0}}{{e}^{-\gamma t}}\] and \[a(t)\,=-\,{{y}^{2\,}}{{x}_{0}}{{e}^{-yt}}\]
(a) When \[t\,=0,\,\,x=\,{{x}_{0}}\,(1\,-\,{{e}^{-0}})=\,0\]
and \[\upsilon
\,=\,y{{x}_{0}}\]
(b) \[x\,(t)\,|{{\,}_{\max
}}\,={{x}_{0,}}\] \[\upsilon \,\,(t)\,|{{\,}_{\max }}\,=y{{x}_{0}}\] \[a(t)\,|{{\,}_{\max
}}\,={{y}^{2}}{{x}_{0}}\]
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