Answer:
(c) \[{{t}_{1}}\,=\,\frac{L/2}{{{V}_{1}}}\,=\,\frac{L}{2{{V}_{1\,}}}\]
and \[{{t}_{2\,}}\,=\,\,\frac{L}{2{{V}_{2}}}\]
\[\therefore \] \[{{U}_{av}}=\,\frac{L}{{{t}_{1\,}}\,+\,{{t}_{1}}}\,=\,\frac{L}{\frac{L}{2}\left(
\frac{1}{{{V}_{1}}}\,+\frac{1}{{{V}_{2}}} \right)}\]
\[=\frac{2{{V}_{1\,}}{{V}_{2}}}{{{V}_{1\,}}\,+\,{{V}_{2}}}\]
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