Answer:
\[\tan \,\theta
=\frac{h}{R}\]
But \[R=\,u\times
\,\sqrt{\frac{2h}{g}}\]
\[\therefore \]\[\,\tan
\,\theta \,=\,\frac{h}{u\times \,\sqrt{\frac{2h}{g}}}\]
or \[\tan \theta
=\,\frac{1}{u}\,\sqrt{\frac{gh}{2}}=\,\frac{1}{200}\,\times
\,\sqrt{\frac{10\times \,1500}{2}}\]
\[=0.4330\]
\[\therefore \]\[\,\theta
=\,{{\tan }^{-1}}\,(0.4330)\,={{23.4}^{o}}.\]
You need to login to perform this action.
You will be redirected in
3 sec