Answer:
(b) \[\cos \,\theta
\,=\,\frac{\vec{A}\cdot
\vec{B}}{|\vec{A}|\,|\vec{B}|}=\frac{(\hat{i}\,+\hat{j})\,(i-\hat{j})}{\sqrt{2}\,\times
\,\sqrt{2}}\,=\frac{1-1}{2}=0\]
\[\therefore \,\theta
=\,\,{{90}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec