Answer:
Gain in PE \[={{U}_{f}}-{{U}_{f}}=-\frac{GMm}{2R}-\left(
-\frac{GMm}{R} \right)\]
\[=\frac{GMm}{R}\left(
-\frac{1}{2}+1 \right)=\frac{GMm}{2R}\]
\[=\frac{{{(gR)}^{2}}m}{2R}=\frac{1}{2}mgR\] \[(as\,\,g=GM/{{R}^{2}})\]
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