Answer:
Here, \[\therefore \]\[\vartriangle V=V-V'=M\left(
\frac{1}{P}-\frac{1}{P'} \right)\]
\[\therefore \]
\[\frac{\vartriangle V}{V}=M\left(
\frac{1}{P}-\frac{1}{P'} \right)\] \[\times \frac{P}{M}=1-\frac{P}{P'}\]
For flow to be laminar, \[\frac{\vartriangle
V}{V}=1-\frac{1\cdot 03\times {{10}^{3}}}{P'}\]
(a)
Now,
\[B=\frac{pV}{\vartriangle V}\]
(b)
Volume flowing per second=
\[\frac{\vartriangle V}{V}=\frac{P}{B}\]
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