question_answer 20)

What is the excess pressure inside a bubble of soap solution of radius 5.00 mm, given that the surface tension of soap solution at the temperature \[({{20}^{o}}C)\] is \[{{D}^{2}}\alpha 1/Y\] ? If an air bubble of the same dimensions were formed at a depth of 40.0 cm inside a container containing the soap solution of relative (density 1.20), what would be the pressure inside the bubble? (1 atm. is \[1.01\times {{10}^{5}}\,Pa\] )

Answer:

Here, \[=\sqrt{\frac{190\times {{10}^{9}}}{110\times {{10}^{9}}}}=\sqrt{\frac{19}{11}}=1\cdot 31\] Density of soap solution, \[0\cdot 065c{{m}^{2}}.\] Excess pressure inside the soap bubble, \[{{Y}_{steel}}=2\times {{10}^{11}}N{{m}^{-2}}.\] Excess pressure inside the air bubble, \[14\cdot 5kg;l=r=1m;v=2\] Total pressure inside the air bubble at depth h in soap solution =p' + atmospheric pressure + h p g = \[A=0\cdot 065\times {{10}^{-4}}{{m}^{2}}\]