Answer:
(a) Here, length of the film supporting the weight \[=40\,cm=0.4\,m\].
Total
weight supported (or force)\[=\frac{F}{AG}\]
Film
has two free surfaces,
\[\therefore
\] Surface tension,
\[=\frac{44500}{\left(
15\cdot 2\times 19\cdot 2\times {{10}^{-6}} \right)\times 42\times
{{10}^{9}}}=3\cdot 65\times {{10}^{-3}}\]
Since the liquid is same for all the cases (a), (b) and (c),
and temperature is also same, therefore surface tension for cases (b) and (c)
will also be the same\[1\cdot 5\]. In Fig. 7(b). 38(b) and (c), the length of
the film supporting the weight is also the same as that of (a), hence the total
weight supported in each case is \[{{10}^{8}}N{{m}^{-2}},\]
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