Answer:
Ideal gas law hold
only if the intermolecular force is negligible or zero.
Here,
radius of hydrogen molecule,
\[r=1,\,\overset{\text{o}}{\mathop{\text{A}}}\,={{10}^{-10}}\,m\]
\[\therefore
\] volume
of 1 molecule of hydrogen\[=\,\frac{4}{3}\,\pi \,{{r}^{3}}\]
\[=\,\frac{4}{3}\,\times
\,3.14\,\times \,{{10}^{-30}}\]
\[=4.19\times
{{10}^{30}}{{m}^{3}}\]
Number
of molecule of hydrogen
\[=0.5\times
6.023\times {{10}^{23}}\]
\[=\text{3}\times
\text{1}{{0}^{\text{23}}}\]
\[\therefore
\] Molecules
volume \[=4.19\times {{10}^{30}}\times 3\times {{10}^{23}}\]
\[=12.6\times
{{10}^{7}}{{m}^{3}}\]
For
ideal gas, \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\]
\[\therefore
\] \[{{V}_{2}}=\,\left( \frac{{{P}_{1}}}{{{P}_{2}}}
\right)\,{{V}_{1}}=\frac{1}{100}\,\times \,{{(3\times {{10}^{-2}})}^{3}}\]
Since
final volume is approximately equal to the molecular volume, so intermolecular
forces cannot be neglected. Hence, ideal gas law cannot hold good in the final
stage.
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