• # question_answer 94)   A compound (A) of boron reacts with $NM{{e}_{3}}$ to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A, B and C. Give the reactions involved.

(A) is diborane, ${{B}_{2}}{{H}_{6}}$. It reacts with $NM{{e}_{3}}$ to form an adduct (B). $\underset{(A)}{\mathop{{{B}_{2}}{{H}_{6}}}}\,+2NM{{e}_{3}}\xrightarrow{{}}\underset{(B)}{\mathop{2B{{H}_{3}}\cdot NM{{e}_{3}}}}\,$ The (B) on hydrolysis gives boric acid,${{H}_{3}}B{{O}_{3}}$. $B{{H}_{3}}\cdot \underset{(B)}{\mathop{NMe}}\,+3{{H}_{2}}O\xrightarrow{{}}\underset{(C)}{\mathop{{{H}_{3}}B{{O}_{3}}}}\,+NM{{e}_{3}}+3{{H}_{2}}$