• # question_answer 77) When $BC{{l}_{3}}$ is treated with water, it hydrolyses and forms${{[B{{(OH)}_{4}}]}^{-}}$ only whereas $AlC{{l}_{3}}$ in acidified aqueous solution forms ${{[Al{{({{H}_{2}}O)}_{6}}]}^{3+}}$ ion. Explain what is the hybridisation of boron and aluminium in these species?

$BC{{l}_{3}}+3{{H}_{2}}O\xrightarrow{{}}B{{(OH)}_{3}}+3HCl$ $B{{(OH)}_{3}}+2{{H}_{2}}O\xrightarrow{{}}{{[B{{(OH)}_{4}}]}^{-}}{{H}_{3}}{{O}^{+}}$ $\ln {{[B{{(OH)}_{4}}]}^{-}}$, boron is in $s{{p}^{3}}$-hybrid state. $AlC{{l}_{3}}+9{{H}_{2}}O\to [Al{{({{H}_{2}}O)}_{6}}]{{(OH)}_{3}}+3HCl$ In${{[Al{{({{H}_{2}}O)}_{6}}]}^{3+}}$, aluminium is in $s{{p}^{3}}{{d}^{2}}$-hybrid state.