Answer:
(i) \[2B{{F}_{3}}+6LiH\to
{{B}_{2}}{{H}_{6}}+6LiF;\]
(ii) \[{{B}_{2}}{{H}_{6}}+6LiH\to
2{{H}_{3}}B{{O}_{3}}+6{{H}_{2}};\]
(iii) \[2NaH+{{B}_{2}}{{H}_{6}}\to 2NaN{{H}_{4}};\]
(v) \[2Al+2NaOH+6{{H}_{2}}O\to
2Na[Al{{(OH)}_{4}}]+3{{H}_{2}};\]
(vi)\[{{B}_{2}}{{H}_{6}}+2N{{H}_{3}}\to
{{B}_{2}}{{H}_{6}}\cdot 2N{{H}_{3}}\]
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