question_answer 51)

Show that the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie wavelength associated with the electron revolving around the orbit.

Answer:

Angular momentum of electron can be calculated as, \[m\upsilon r=\frac{h}{2\pi }\] \[2\,\pi r=n\frac{h}{m\upsilon }\] \[2\,\,\pi r=n\lambda \] Circumference \[=n\times \,de\] Broglie wavelength of electron