question_answer 64)

  16 g of oxygen has same number of molecules as in : (a) 16 g of \[CO\]              (b) 28 g of \[{{N}_{2}}\] (c) 14 g of \[{{N}_{2}}\]                  (d) 1.0 g of \[{{H}_{2}}\]           

Answer:

  (c, d) Number of molecules of \[{{O}_{2}}\] in 16 g \[{{O}_{2}}\] \[=\frac{16}{32}\times 6.023\times {{10}^{23}}\] \[=0.5\times 6.023\times {{10}^{23}}\] 0.5 moles are present in 14 g \[{{N}_{2}}\] and 1 g \[{{H}_{2}}\], hence these samples will also have \[(0.5\times 6.023\times {{10}^{23}})\]) molecules. (c) Number of molecules of \[{{N}_{2}}\]                              \[=\frac{w}{mol.wt}\times 6.023\times {{10}^{23}}\]                 \[=\frac{14}{28}\times 6.023\times {{10}^{23}}\]                 \[=0.5\times 6.023\times {{10}^{23}}\] Number of molecules of \[{{H}_{2}}=\frac{1}{2}\times 6.023\times {{10}^{23}}\] \[=0.5\times 6.023\times {{10}^{23}}\]