Answer:
(c, d) (c) Number of atoms of
Nitrogen
\[=\frac{\text{Mass}\,}{\text{Atomic}\,\text{mass}}\times
6.023\times {{10}^{23}}\]
\[=\frac{28}{14}\times
6.023\times {{10}^{23}}\]
\[=2\times 6.023\times
{{10}^{23}}\]
Number of atoms of Oxygen
\[=\frac{32}{16}\times
6.023\times {{10}^{23}}\]
\[=2\times 6.023\times
{{10}^{23}}\]
(d) Number of atoms of Carbon
\[=\frac{12}{12}\times
6.023\times {{10}^{23}}\]
\[=6.023\times {{10}^{23}}\]
Number of atoms of Sodium
\[=\frac{23}{23}\times 6.023\times
{{10}^{23}}\]
\[=6.023\times {{10}^{23}}\]
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