• # question_answer 9) Find the oxidation state of sodium in$N{{a}_{2}}{{O}_{2}}$.

Let $x$ be the oxidation state of Na in$N{{a}_{2}}{{O}_{2}}$. $O_{2}^{2-}$is a peroxo linkage in which O has oxidation state (-1). $\therefore$ $2x+2\times (-1)=0$ or $x=+1$