Answer:
The compound (A) is quick lime, \[CaO\].
This combines with and forms calcium hydroxide, \[Ca{{(OH)}_{2}}\].
\[\underset{\underset{Calcium\,oxide}{\mathop{(A)}}\,}{\mathop{CaO}}\,+{{H}_{2}}O\to
\underset{\begin{smallmatrix}
(B) \\
Calcium\,hydroxide
\end{smallmatrix}}{\mathop{Ca{{(OH)}_{2}}}}\,\]
When \[C{{O}_{2}}\] is passed through
the solution having \[Ca{{(OH)}_{2}}\], the solution turns milky due to
formation of calcium carbonate, \[CaC{{O}_{3}}\].
\[Ca{{(OH)}_{2}}+C{{O}_{2}}\to
\underset{\begin{smallmatrix}
(C) \\
(Milkiness)
\\
Calcium\,carbonate
\end{smallmatrix}}{\mathop{CaC{{O}_{3}}}}\,+{{H}_{2}}O\]
When excess of \[C{{O}_{2}}\] is passed
into milky solution, the milkiness disappears due to formation of calcium
bicarbonate, \[Ca{{(HC{{O}_{3}})}_{2}}\] which is soluble.
\[CaC{{O}_{3}}+{{H}_{2}}O+C{{O}_{2}}\to
\underset{Calcium\,bicarbonte}{\mathop{Ca{{(HC{{O}_{3}})}_{2}}}}\,\]
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