• question_answer 3) Why is $K{{O}_{2}}$ paramagnetic?

The superoxide $O_{2}^{-}$ is paramagnetic because of one unpaired electron in ${{\pi }^{*}}2p$ molecular orbital. $KK\sigma {{(2s)}^{2}}{{\sigma }^{*}}{{(2s)}^{2}}\sigma {{(2{{p}_{x}})}^{2}}\pi {{(2{{p}_{x}})}^{2}}{{(\pi 2{{p}_{y}})}^{2}}{{\pi }^{*}}{{(2{{p}_{x}})}^{2}}{{\pi }^{*}}{{(2{{p}_{y}})}^{1}}$