Answer:
In
\[{{(CN)}_{2}}\], oxidation state of carbon will be:
\[2x-6=0,\,\] \[x=+3\]
Similarly in\[C{{N}^{-}}\], \[x-3=-1,\] \[x=+2\]
\[CN{{O}^{-}},\] \[x-3-2=-1,\]
\[x=+4\]
The reaction shows disproportionation in which cyanogen \[{{(CN)}_{2}}\]
is reduced to \[(C{{N}^{-}})\] and oxidised to \[(C{{N}^{-}})\]ion.
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