Answer:
(i) \[\underset{Anode}{\mathop{Zn(s)|Z{{n}^{2+}}}}\,||\underset{Cathode}{\mathop{A{{g}^{+}}|Ag(s)}}\,\]
Oxidation takes place at anode and reduction at cathode.
(ii) Electrons
(iii) \[Zn(s)\to Z{{n}^{2+}}+2{{e}^{-}}\](Anode)
\[C{{u}^{2+}}+2e\to Cu(s)\] (Cathode)
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