Answer:
(a, d)\[H\overset{sp}{\mathop{C}}\,\equiv
\overset{sp}{\mathop{C}}\,-\overset{sp}{\mathop{C}}\,\equiv
\overset{sp}{\mathop{C}}\,-H\]and \[\overset{s{{p}^{2}}}{\mathop{{{H}_{2}}C}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,\]
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