Answer:
(a) \[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-Cl\] (b)
\[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{\underset{\text{O}}{\mathop{\text{
}\!\!|\!\!\text{ }\!\!|\!\!\text{
}}}\,}{\mathop{\overset{s{{p}^{2}}}{\mathop{C}}\,}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\] (c)
\[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{sp}{\mathop{C}}\,\equiv
N\] (d) \[H-\underset{\underset{\text{O}}{\mathop{\text{ }\!\!|\!\!\text{
}\!\!|\!\!\text{
}}}\,}{\mathop{\overset{s{{p}^{2}}}{\mathop{C}}\,}}\,-N{{H}_{2}}\]
(e) \[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{sp}{\mathop{C}}\,\equiv
N\]
You need to login to perform this action.
You will be redirected in
3 sec