• # question_answer 64)   What will be the product obtained as a result of the following reaction and why?

The reaction under consideration is an example of Friedel-Craft alkylation. The electrophile formed in presence of $AlC{{l}_{3}}$i.e., $C{{H}_{3}}-C{{H}_{2}}-\overset{+}{\mathop{C{{H}_{2}}}}\,$undergo isomerisation to give more stable $C{{H}_{3}}-\overset{+}{\mathop{CH}}\,-C{{H}_{3}}$ ion. The product obtained in the reaction is, therefore, isopropyl benzene or cumene. $\underset{n-\text{Propyl}\,chloride}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Cl}}\,+AlC{{l}_{3}}\xrightarrow{{}}\underset{{{1}^{{}^\circ }}Carbocation}{\mathop{C{{H}_{3}}C{{H}_{2}}\overset{+}{\mathop{C{{H}_{2}}}}\,}}\,+AlCl_{4}^{-}$$C{{H}_{3}}\underset{(1{}^\circ )}{\mathop{C{{H}_{2}}}}\,\overset{+}{\mathop{C}}\,{{H}_{2}}\xrightarrow{{}}\underset{(2{}^\circ )\,more\,\,stable}{\mathop{C{{H}_{3}}}}\,\overset{+}{\mathop{C}}\,HC{{H}_{3}}$