Answer:
(a)(i)
\[C{{H}_{3}}\underset{But-1-ene}{\mathop{C{{H}_{2}}CH}}\,=C{{H}_{2}}\]
(ii) \[\underset{But-2-ene\,(cis)}{\mathop{\underset{\begin{smallmatrix}
\\
C{{H}_{3}}
\end{smallmatrix}}{\mathop{C{{H}_{3}}}}\,\underset{\begin{smallmatrix}
\\
-
\end{smallmatrix}}{\mathop{-}}\,\underset{\begin{smallmatrix}
\parallel \\
C
\end{smallmatrix}}{\mathop{C}}\,\underset{\begin{smallmatrix}
\\
-
\end{smallmatrix}}{\mathop{-}}\,\underset{\begin{smallmatrix}
\\
H
\end{smallmatrix}}{\mathop{H}}\,}}\,\]
(iii) \[C{{H}_{3}}-\underset{\underset{\underset{But-2-ene}{\mathop{\text{H-C-C}{{\text{H}}_{\text{3}}}}}\,}{\mathop{||}}\,}{\mathop{C}}\,-H\]
(iv) \[\underset{2-Mrthylprop-1-ene}{\mathop{C{{H}_{3}}-\overset{\overset{\text{C}{{\text{H}}_{\text{3}}}}{\mathop{|}}\,}{\mathop{C}}\,=C{{H}_{2}}}}\,\]
(b) (i) \[\underset{Pent-1-yne}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-C\equiv
CH}}\,\]
(ii) \[\underset{Pent-2-yne}{\mathop{C{{H}_{3}}C{{H}_{2}}-C\equiv
C-C{{H}_{3}}}}\,\]
(iii) \[\underset{3-Methylbut-1-yne}{\mathop{C{{H}_{3}}-\overset{\overset{\text{C}{{\text{H}}_{\text{3}}}}{\mathop{|}}\,}{\mathop{C}}\,-C\equiv
CH}}\,\]
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