Answer:
(a) On cooling, the solution
becomes pink, i.e., it shifts in backward direction:
\[\underset{(pink)}{\mathop{{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}}}\,(aq)+4C{{l}^{-}}(aq)\underset{{}}{\leftrightarrows}\]\[\underset{(blue)}{\mathop{{{[CoC{{l}_{4}}]}^{2-}}}}\,(aq)+6{{H}_{2}}O(l)\]
It means, reaction will be
endothermic, i.e., \[\Delta H>0\].
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