Answer:
Information shadow:
The reaction is:
\[2S{{O}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2S{{O}_{3}}(g)\]
\[\Delta {{n}_{g}}=2-3=-1\]
\[{{K}_{p}}=2\times
{{10}^{10}}ba{{r}^{-1}}\]
Problem
solving strategy:
\[{{K}_{p}}={{K}_{c}}\times {{(RT)}^{\Delta {{n}_{g}}}}\]
\[{{K}_{c}}={{K}_{p}}/{{(RT)}^{\Delta {{n}_{g}}}}\]
Working
it out (i)
\[{{K}_{c}}=\frac{2\times {{10}^{10}}}{{{(0.083\times 450)}^{-1}}}\]
\[=7.47\times
{{10}^{11}}mo{{l}^{-1}}L\]
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