Answer:
The given reaction is:
\[\underset{{{t}_{eq}}}{\overset{{}}{\mathop{{{t}_{0}}}}}\,\underset{\underset{(0.1-x)}{\mathop{0.1}}\,}{\mathop{CO(g)}}\,+\underset{\underset{(0.1-x)}{\mathop{0.1}}\,}{\mathop{{{H}_{2}}O(g)}}\,\rightleftharpoons
\underset{\begin{smallmatrix}
0 \\
x
\end{smallmatrix}}{\mathop{C{{O}_{2}}(g)}}\,+\underset{\underset{x}{\mathop{0}}\,}{\mathop{{{H}_{2}}(g)}}\,\]
\[{{K}_{c}}=\frac{[C{{O}_{2}}][{{H}_{2}}]}{[CO][{{H}_{2}}O]}\]
\[4.24=\frac{x\times
x}{(0.1-x)(0.1-x)}\]
\[\sqrt{4.24}=\frac{x}{0.1-x}\]
\[2.06=\frac{x}{0.1-x}\]
\[2.06(0.1-x)=x\]
\[x=0.067\]
\[\therefore
\] \[[C{{O}_{2}}]=[{{H}_{2}}]=0.06M\]
\[[C{{O}_{2}}]=[{{H}_{2}}O]=0.1-0.067\]
\[=0.033M\]
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