Answer:
We are given that, diameter of the wire, D = 0.5 mm = 0.5 × 10?3 m resistivity of copper, = 1.6 × 10?6 ohm cm = 1.6 × 10?8 ohm m required resistance, R = 10 ohm
As
R = , = [A = = ]
or
m = 112.7 m
Since, R
= , R 1/D2. When D is doubled, R becomes times.
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