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VIT Engineering VIT Engineering Solved Paper-2011

  • question_answer
    The order and degree of the differential equation \[{{\left( 1+4\frac{dy}{dx} \right)}^{2/3}}=4\frac{{{d}^{2}}y}{d{{x}^{2}}}\] are respectively

    A)  \[1,\,\frac{2}{3}\]

    B)  \[3,\,2\]

    C)  \[2,\,3\]

    D)  \[2,\,\frac{2}{3}\]

    Correct Answer: C

    Solution :

    Given differential equation is \[{{\left( 1+4\frac{dy}{dx} \right)}^{2/3}}=4\frac{{{d}^{2}}y}{d{{x}^{2}}}\] \[{{\left( 1+4\frac{dy}{dx} \right)}^{2}}={{4}^{3}}{{\left( \frac{{{d}^{2}}y}{d{{x}^{2}}} \right)}^{3}}\] Here, order is  and degree is 3.


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