VIT Engineering VIT Engineering Solved Paper-2011

  • question_answer
    If \[I=\left[ \begin{matrix}   1 & 0  \\    0 & 1  \\ \end{matrix} \right],\] \[J=\left[ \begin{matrix}    0 & 1  \\    -1 & 0  \\ \end{matrix} \right]\] and \[B=\left[ \begin{matrix}    \cos \theta  & \sin \theta   \\    -\sin \theta  & \cos \theta   \\ \end{matrix} \right],\] then B is equal to

    A)  \[I\cos \theta +J\sin \theta \]

    B)  \[I\,\sin \theta +J\,\cos \theta \]

    C)  \[I\cos \theta -J\sin \theta \]

    D)  \[-I\cos \theta +J\sin \theta \]

    Correct Answer: A

    Solution :

    \[B=\left[ \begin{matrix}    \cos \theta  & \sin \theta   \\    -\sin \theta  & \cos \theta   \\ \end{matrix} \right]\]         \[=\left[ \begin{matrix}    \cos \theta  & 0  \\    0 & \cos \theta   \\ \end{matrix} \right]+\left[ \begin{matrix}    0 & \sin \theta   \\    -\sin \theta  & 0  \\ \end{matrix} \right]\]     \[=\cos \theta \left[ \begin{matrix}    1 & 0  \\    0 & 1  \\ \end{matrix} \right]+\sin \theta \left[ \begin{matrix}    0 & 1  \\    -1 & 0  \\ \end{matrix} \right]\]     \[=I\cos \theta +J\sin \theta \]


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