A) \[CN>O_{2}^{+}\]
B) \[CN={{N}_{2}}\]
C) \[{{N}_{2}}<{{O}_{2}}\]
D) \[H_{2}^{+}>He_{2}^{+}\]
Correct Answer: D
Solution :
Bond order oc stability When the bond order of two molecules are same, the molecule with least number of antiboding electrons is more stable. Thus, \[H_{2}^{+}(l)=\sigma 1{{s}^{1}}\] \[BO=\frac{1-0}{2}=0.5\] \[He_{2}^{+}(3)=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{1}}\] \[BO=\frac{2-1}{2}=0.5\] Hence, stability of \[H_{2}^{+}>\] stability of \[He_{2}^{+}\]
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