question_answer

A vessel at 1000 K contains \[C{{O}_{2}}\] with a pressure of 0.5 atm. Some of the \[C{{O}_{2}}\] is converted into \[CO\] on the addition of graphite. The value of K if the total pressure at equilibrium is 0.8 atm, is

A)  \[1.8atm\]        

B)  \[3atm\]

C)  \[0.3atm\]

D)  \[0.18atm\]

Correct Answer: A

Solution :

\[\therefore \] \[(0.5-x)+2x=0.8\] \[x=0.3atm.\] \[\therefore \] \[{{p}_{C{{O}_{2}}}}=0.5-0.3=0.2\] \[{{p}_{CO}}=2x=2\times 0.3=0.6atm\] \[K=\frac{p_{CO}^{2}}{{{p}_{C{{O}_{2}}}}}=\frac{{{(0.6)}^{2}}}{0.2}=1.8atm\]