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VIT Engineering VIT Engineering Solved Paper-2011

  • question_answer
    The rate constant of a reaction at temperature 200 K is 10 times less than the rate constant at 400 K. What is the activation energy of the reaction?

    A)  \[1842.4\text{ }R\]      

    B)  \[460.6\text{ }R\]

    C)  \[230.3\text{ }R\]

    D)  \[921.2\text{ }R\]

    Correct Answer: D

    Solution :

     At  \[{{T}_{1}}=200K,\] if \[{{k}_{1}}=k\] then at \[{{T}_{2}}=400K,\,\,{{k}_{2}}=10k\] \[\log \frac{10k}{k}=\frac{{{E}_{a}}}{2.303R}\left( \frac{400-200}{400\times 200} \right)\] \[{{E}_{a=}}921.2R\]


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