A) \[Z-3,A-4\]
B) \[Z-1,A-4\]
C) \[Z-2,A-4\]
D) \[Z,A-2\]
Correct Answer: A
Solution :
\[_{Z}^{A}X\to _{2}^{4}He+_{Z-2}^{A-2}Y\] \[_{Z-2}^{A-4}Y\to {{e}^{+}}+_{Z-3}^{A-4}Y\] During \[{{\beta }^{-}}\] emission. \[_{t}{{P}^{1}}{{\to }_{0}}{{n}^{1}}+{{\beta }^{+}}\] The proton changes into neutron. So, charge number decreases by 1 but mass number remains unchanged.
You need to login to perform this action.
You will be redirected in
3 sec
