VIT Engineering VIT Engineering Solved Paper-2011

  • question_answer
    The ratio of momentum of an electron and \[\alpha \]-particle which are accelerated from rest by a potential difference of 100 V is

    A)  1    

    B)  \[\sqrt{(\text{2}{{\text{m}}_{\text{e}}}/{{\text{m}}_{\alpha }})}\]

    C)  \[\sqrt{({{\text{m}}_{\text{e}}}/{{\text{m}}_{\alpha }})}\]     

    D)  \[\sqrt{(\text{m},/\text{2}{{\text{m}}_{\alpha }})}\]

    Correct Answer: D

    Solution :

    \[\frac{1}{2}m{{v}^{2}}=eV\] \[\Rightarrow \] \[v=\sqrt{\frac{2eV}{m}}\] \[p=mv=\sqrt{2mev}\] Now, \[{{p}_{e}}=\sqrt{2{{m}_{e}}\times e\times 100}\] and \[{{p}_{\alpha }}=\sqrt{4{{m}_{e}}\times e\times 100}\] \[\therefore \] \[\frac{{{p}_{e}}}{{{p}_{\alpha }}}=\sqrt{\frac{{{m}_{e}}}{2{{m}_{\alpha }}}}\]


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